95=5w^2+35

Solution for 95=5w^2+35 equation:

95=5w^2+35

We move all terms to the left:

95-(5w^2+35)=0

We get rid of parentheses

-5w^2-35+95=0

We add all the numbers together, and all the variables

-5w^2+60=0

a = -5; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-5)·60
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*-5}=\frac{0-20\sqrt{3}}{-10}
=-\frac{20\sqrt{3}}{-10}
=-\frac{2\sqrt{3}}{-1}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*-5}=\frac{0+20\sqrt{3}}{-10}
=\frac{20\sqrt{3}}{-10}
=\frac{2\sqrt{3}}{-1}
$